{"id":11765,"date":"2026-02-19T07:21:04","date_gmt":"2026-02-19T07:21:04","guid":{"rendered":"https:\/\/www.coinspeaker.com\/tr\/?p=11765"},"modified":"2026-02-19T07:21:04","modified_gmt":"2026-02-19T07:21:04","slug":"xrp-fiyat-tahmini-haziranda-70-dolar-olur-mu","status":"publish","type":"post","link":"https:\/\/www.coinspeaker.com\/tr\/xrp-fiyat-tahmini-haziranda-70-dolar-olur-mu\/","title":{"rendered":"XRP 2026 Fiyat Tahmini: Ripple\u2019\u0131n XRP Coini Haziranda 70$ Olur Mu?"},"content":{"rendered":"

Kripto piyasas\u0131, agresif spek\u00fclasyonlarla hareket eder. Bununla birlikte, ekosistemdeki her tahmin ayn\u0131 etkiyi yaratmaz.<\/p>\n

Son g\u00fcnlerde yap\u0131lan \u201cXRP Haziran\u2019da 70 dolara \u00e7\u0131kabilir\u201d iddias\u0131, bunu ba\u015faran \u00f6rneklerden biri oldu.<\/p>\n

Olumlu hava yenilikleri beslese de, sahadaki ger\u00e7ek \u00e7o\u011fu zaman farkl\u0131 konu\u015fur. Bu nedenle bu \u00f6ng\u00f6r\u00fc, kripto toplulu\u011funda tart\u0131\u015fmal\u0131 bir ba\u015fl\u0131k h\u00e2line geldi.<\/p>\n

Yat\u0131r\u0131mc\u0131lar\u0131 \u015fa\u015f\u0131rtan iddia, BSCNews\u2019in \u201cCryptoBull\u201d adl\u0131 anonim bir analistten bahsetti\u011fi payla\u015f\u0131mla g\u00fc\u00e7 kazand\u0131.<\/p>\n

A\u00e7\u0131klama k\u0131sa s\u00fcrede yay\u0131ld\u0131. Ancak iddian\u0131n b\u00fcy\u00fckl\u00fc\u011f\u00fc nedeniyle bir\u00e7ok ki\u015fide \u015f\u00fcphe de uyand\u0131rd\u0131.<\/p>\n

Sonu\u00e7 olarak destekleyenler ve kar\u015f\u0131 \u00e7\u0131kanlar, tahminin ne kadar rasyonel oldu\u011funu tart\u0131\u015fmaya ba\u015flad\u0131.<\/p>\n

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\ud83d\udea8MARKETS: ANALYST PREDICTS $XRP<\/a> TO HIT $70 BY JULY<\/p>\n

The pseudonymous and aptly-named 'CryptoBull' believes that @Ripple<\/a>'s $XRP<\/a> is "lined up" to reach $70 by the end of June.<\/p>\n

The prediction is intuitively ridiculous and would mean a 47x increase from current prices and a market\u2026 pic.twitter.com\/a7KuboDt2H<\/a><\/p>\n

— BSCN (@BSCNews) February 18, 2026<\/a><\/p><\/blockquote>\n